Answer:
The emf induced in this coil at the given time is 12 V
Explanation:
Given;
a coil with a self-inductance, L = 6.0 H
rate of change of current in the coil, di/dt = 2.0 A/s
The emf induced in this coil at t = 0 s, is calculated as;
[tex]emf = L \frac{di}{dt}[/tex]
where;
L is the inductance (H)
[tex]\frac{di}{dt}[/tex] is the rate of change of time (A/s)
Substitute in the given values and solve for the emf
[tex]emf = L\frac{di}{dt} \\\\emf = 6*2\\\\emf = 12 \ V[/tex]
Therefore, the emf induced in this coil at the given time is 12 V
