Answer:
[tex]3217 \: {in}^{2} [/tex]
Solution,
Diameter (d)= 32 in
Radius (r)= 32/2= 16 in
Surface area of sphere:
[tex]4\pi {r}^{2} \\ = 4 \times \pi \times {(16)}^{2} \\ = 4 \times \pi \times 256 \\ = 1024\pi \\ = 1024 \times 3.142 \\ = 3217.108 \: {in}^{2} [/tex]
Hope this helps...
Good luck on your assignment...
