the density of ethanol is 1.09g/cm^3 the density of propylene is 0.97g/cm^3 80 litres of ethanol are mixed with 148 litres of propylene to make 228 litres of antifreeze work out the density of the antifreeze in g/cm^3

To calculate the density of the final mixture we need to know the mass of each solution used is. We will also need to convert the volumes from litres to cm³, to do that we can just multiply 1000.

For the ethanol:

[tex]mass = volume*density\\mass = (80*1000)*1.09 = 87,200 \text{ g}\\[/tex]

For the propylene:

[tex]mass = (148*1000)*0.97 = 143,560 \text{ g}[/tex]

So the mass in the final mix is the sum of both:

[tex]mass_{final} = 87200 + 143560 = 230,760 \text{ g}[/tex]

Therefore the density is:

[tex]density_{final} = \frac{230760}{228000} = 1.012 \text{ }\frac{g}{cm^3}[/tex]

raphealnwobi raphealnwobi · Answer 2 · 2021-12-07T10:56:25+01:00

The density of the antifreeze is 1.01 g/cm³

Equations are used to show the relationship between two or more numbers and variables.

Let x represent the density of the antifreeze in g/cm^3.

1 cm³ = 0.001 L

80 L = 80000 cm³; 148 L = 148000 cm³, 228 L = 228000 cm³

Hence:

(1.09 * 80000) + (0.97 * 148000) = x * 228000

228000x = 230760

x = 1.01 g/cm³

The density of the antifreeze is 1.01 g/cm³

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