Answer:
[tex]\boxed{no \: \: \: solution}[/tex]
Step-by-step explanation:
[tex] \frac{4x}{x - 3} = 7 + \frac{12}{x - 3} \\ \frac{4x}{x -3 } = \frac{7(x - 3)}{1(x - 3)} + \frac{12}{x - 3} \\ \frac{4x}{x - 3} = \frac{7x - 21 + 12}{x - 3} \\ \frac{4x}{x - 3} = \frac{7x - 9}{x - 3} \\\red{ use \: \: \: cross \: \: multipication} \\ 4x(x - 3) = (x - 3)(7x - 9) \\ 4 {x}^{2} - 12 = 7 {x}^{2} - 9x - 21x + 27 \\4 {x}^{2} - 12 = 7 {x}^{2} - 30x + 27[/tex]
So the answer has to be no solution
