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At the movie theatre, child admission is $5.10 and adult admission is $9.00 .
On Wensday, twice as many adults tickets as child tickets were for a total of $831.60.

How many child tickets were sold that day?

At the movie theatre child admission is 510 and adult admission is 900 On Wensday twice as many adults tickets as child tickets were for a total of 83160 How ma class=

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Answer:

[tex] 5.10 X +9.00 Y = 831.60[/tex]

We also know that for Wedneday we have two times tickets for adults compared to child so we have

[tex] Y =2x[/tex]

And using this condition we have:

[tex] 5.10 X + 18 X = 831.60[/tex]

And solving for X we got:

[tex] X= \frac{831.60}{23.1}=36[/tex]

So then the number of tickets sold for child are 36

Step-by-step explanation:

For this problem we can set upt the following notation

X = number of tickets for child

Y= number of tickets for adults

And we know that the total revenue  for Wednesday was 831.60. So then we can set up the following equation for the total revenue

[tex] 5.10 X +9.00 Y = 831.60[/tex]

We also know that for Wedneday we have two times tickets for adults compared to child so we have

[tex] Y =2x[/tex]

And using this condition we have:

[tex] 5.10 X + 18 X = 831.60[/tex]

And solving for X we got:

[tex] X= \frac{831.60}{23.1}=36[/tex]

So then the number of tickets sold for child are 36

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