Answer: 0.20
Step-by-step explanation:
As per given :
P(student enrolled in a math class ) = 65% = 0.65
P( student enrolled in a science class) = 43%= 0.43
P( student enrolled in both ) = 13% = 0.13
Formula of conditional probability :
[tex]P(A|B)=\dfrac{P(A\text{ and }B)}{P(B)}[/tex]
Using the above formula,
The probability that the student is enrolled in a science class given that he is enrolled in maths class :
[tex]P(\text{science}|\text{math})=\dfrac{P(\text{science and maths})}{P(\text{math})}\\\\=\dfrac{0.13}{0.65}\\\\=\dfrac{13}{65}\\\\=\dfrac{1}{5}=0.20[/tex]
Hence, the probability that the student is also enrolled in a science class = 0.20 .
