Answer:
d. A weak base
Explanation:
For this question, we have to start with the reaction between [tex]HF[/tex] and [tex]NaOH[/tex]. So:
[tex]HF~+~NaOH~->~NaF~+~H_2O[/tex]
Now, we have to analyze each compound:
Fluorhydric acid HF this is a strong acid because it has the ability to produce hydronium ions [tex]H^+[/tex]
Sodium hydroxide NaOH this is a strong base because it has the ability to produce hydroxide ions [tex]OH^-[/tex]
Sodium fluoride NaF is a salt in which the cation is [tex]Na^+[/tex] and the anion is [tex]F^-[/tex]
Water Is a neutral molecule usually the solvent
Now, we have the reaction of a strong acid with a strong base. If we remember the conjugated base theory, a strong acid will produce a weak base. So, NaF is a weak base. We also have water, but this is a neutral molecule. With this in mind, the answer is d.
I hope it helps!