As the result of experimental work, a student finds the density of a liquid to be 0.1369 g/㎤. The known density of that liquid is 0.1478 g/㎤. What is the percent error of this student's work? (Round final answer to the nearest tenth if necessary​

Respuesta :

Answer:

Percent error is [tex]7.4\%[/tex]

Step-by-step explanation:

Given:

As per the result of experimental work, density of a liquid is 0.1369 g/㎤

Known density of the liquid is 0.1478 g/㎤

To find: percent error

Solution:

The density of a substance is defined as mass per unit volume.

S.I. unit is Kilogram per cubic metre.

Error = Actual density - density as per the experiment = [tex]0.1478-0.1369=1.0109\,\,g/cm^3[/tex]

Percent error = ( error/Actual error ) × 100 = [tex]\frac{0.0109}{0.1478}\times 100=7.4\%[/tex]