Let f(x) = 9x3 + 21x2 − 14 and g(x) = 3x + 1. Find f of x over g of x. 3 times x squared plus 6 times x minus 2 minus 12 over the quantity 3 times x plus 1 3 times x squared plus 6 times x minus 2 plus 12 over the quantity 3 times x plus 1 3 times x squared plus 6 times x plus 2 minus 12 over the quantity 3 times x plus 1 3 times x squared plus 6 times x plus 2 plus 12 over the quantity 3 times x plus 1

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Answer:

A. 3x²+6x-2- [tex]\frac{12}{3x+1}[/tex]

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Answer:

a.

i took the exam and got it right:)

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