Answer:
(a) the image is attached below
(b) v = 0.237 m/s
Explanation:
(a) The free-body diagram can be observed in the attached image
(b) To find the maximum speed you take into account the centripetal force:
[tex]F_c=ma_c=m\frac{v^2}{r}[/tex]
m: mass = 0.80kg
v: tangential speed of the stone = ?
r: radius of the circular trajectory of the stone = 0.90mm = 0.90*10^-3 m
The force cannot exceed 50.0N, then you have:
[tex]50.0N=m\frac{v^2}{r}\\\\v=\sqrt{\frac{(50.0N)r}{m}}=\sqrt{\frac{(50.0N)(0.90*10^{-3}m)}{0.80kg}}\\\\v=0.237\frac{m}{s}[/tex]
hence, the maximum speed the stone can attain without breaking the string is 0.237m/s
