Answer:
529.6 g Cd₃N₂
General Formulas and Concepts:
Math
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Chemistry
Atomic Structure
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
Step 1: Define
1.450 mol Cd₃N₂
Step 2: Identify Conversions
Molar Mass of Cd - 112.41 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of Cd₃N₂ - 3(112.41) + 2(14.01) = 365.25 g/mol
Step 3: Convert
[tex]\displaystyle 1.450 \ mol \ Cd_3N_2(\frac{365.25 \ g \ Cd_3N_2}{1 \ mol \ Cd_3N_2} ) = 529.613 \ g \ Cd_3N_2[/tex]
Step 4: Check
Follow sig fig rules and round. We are given 4 sig figs.
529.613 g Cd₃N₂ ≈ 529.6 g Cd₃N₂
