Answer:
Option (4).
Step-by-step explanation:
Outer diameter of the hollow metallic ball = 10 centimeters
Outer radius of this ball = [tex]\frac{10}{2}[/tex] = 5 cm
Volume of the outer ball [tex]V_{1}[/tex] = [tex]\frac{4}{3}\pi (r)^3[/tex]
= [tex]\frac{4}{3}\pi (5)^3[/tex]
Inner radius of the hollow metallic ball = (5 - 1) = 4 cm
Volume of the inner hollow ball [tex]V_{2}[/tex] = [tex]\frac{4}{3}\pi (4)^3[/tex]
Volume of the metal used in the metallic ball = [tex]V_{1}-V_{2}[/tex]
= [tex]\frac{4}{3}\pi (5)^3-\frac{4}{3}\pi (4)^{3}[/tex]
= [tex]\frac{4}{3}\pi [(5)^3-(4)^3][/tex]
Therefore, expression given in option (4) will be used to measure the volume of the hollow metallic ball.
