Answer:
1.63 m
11.3 m
Explanation:
Given:
v₀ₓ = 9.8 m/s
v₀ᵧ = 9.8 tan 30° = 5.67 m/s
aₓ = 0 m/s²
aᵧ = -9.8 m/s²
Find: Δy given vᵧ = 0 m/s.
vᵧ² = v₀ᵧ² + 2aᵧΔy
(0 m/s)² = (5.67 m/s)² + 2 (-9.8 m/s²) Δy
Δy = 1.63 m
Find: Δx given Δy = 0 m.
Δy = v₀ᵧ t + ½ aᵧt²
0 m = (5.67 m/s) t + ½ (-9.8 m/s²) t²
t = 1.15 s
Δx = v₀ₓ t + ½ aₓt²
Δx = (9.8 m/s) (1.15 s) + ½ (0 m/s²) (1.15 s)²
Δx = 11.3 m
