Answer: The answer in three significant figures is [tex]0.610K/s[/tex]
Explanation:
We need to see the relation between milliK and K which is :
[tex]1mK=10^{-3}K[/tex]
Thus [tex]1mK/s=10^{-3}K/s[/tex]
Using unitary method:
If [tex]1mK/s=10^{-3}K/s[/tex]
[tex]610mK/s=\frac{10^{-3}K/s}{1mK/s}\times 610mK/s\\\\=0.610mK/s[/tex]
Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.
Thus the answer in three significant figures is [tex]0.610K/s[/tex]
