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A commercial airplane travels 5,000 feet east and then ascends 3,000 feet from its starting point in the sky. Upon noticing a severe storm system on the horizon, the pilot decides to return to the starting point. A) how much distance does the plane have to travel to turn back? B) at what angle would the plane need to travel to return to its starting point. (1,000 feet = 1 unit)

Respuesta :

Answer:

A) 5830.95 B)59.04

Step-by-step explanation:

Solve for the hypotenuse of 5,000 and 3,000

Use tangent to find the angle

tanx = 5,000/3,000

x=59.04

kapoorprachi783

The distance the plane has to travel to turn back is 5830.95 km.

The angle would the plane need to travel to return to its starting point is 59.04°

How to find the distance?

Solve for the hypotenuse of 5,000 and 3,000

Use tangent to find the angle

tanx = 5,000/3,000

x = 59.04

Height is the size of an object in the vertical course and distance is the measurement of an object from a specific factor in the horizontal route.

Learn more about Height and distance here: https://brainly.com/question/25638875

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