The soccer team is planning to sell health bars for a fundraiser. The prices of purchasing health bars from two different companies are represented by the system of equations shown, where x is the number of bars purchased and y is the total cost in dollars.

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Answer:

Team will need to purchase 40 bars from each company.

Step-by-step explanation:

The given question is incomplete; here is the complete question.

"The soccer team is planning to sell health bars for a fundraiser. The prices of purchasing health bars from two different companies are represented by the system of equations shown, where x is the number of bars purchased and y is the total cost in dollars. Company A: y = 0.75x. Company B: y = (10 + 0.50x). How many bars would the team need to purchase from each company in order for the total cost to be equal?"

Equation for company A,

y = 0.75x

And equation for the company B,

y = 0.5x + 10

where y = cost of the bars

and x = number of bars purchased

If cost of the bars are same for both the companies.

0.75x = 0.5x + 10

0.75x - 0.5x = (0.5x + 10) - 0.5x

0.25x = 10

x = [tex]\frac{10}{0.25}[/tex]

x = 40 health bars

Therefore, the team will need to purchase 40 health bars.

Answer:

The correct answer is 40 bars.

Step-by-step explanation:

In order to find this amount we have to find when the y values are worth the same. Since both equations are equal to y, we can set them equal to each other to find a time when the y values are the same.

Company A = Company B

.75x = 10 + .50x ---> Now subtract .50x from both sides.

.25x = 10 ---> Now divide both sides by .25

x = 40

When x = 40 it will cost $30 from both companies.