Answer:
The length and width of the field are 68ft and 32ft respectively
Step-by-step explanation:
Given:
Rectangular Playing Field
Perimeter. P = 200 ft
Required
The dimension of the field (Length and Width)
Let L and W represent the length and the width of the field.
From the question, L is 4 more than twice of W.
This means
L = 4 + 2W
Provided that the playing field is rectangular in shape;
We need to make use of the formula of perimeter of a rectangle.
P = 2(L + W)
Substitute 200 for P
200 = 2(L + W)
Divide through by 2
[tex]\frac{200}{2} = \frac{2(L + W)}{2}[/tex]
100 = L + W
Recall that L = 4 + 2W
Substitute 4 + 2W for L
100 = L + W becomes
100 = 4 + 2W + W
100 = 4 + 3W
Subtract 4 form both sides
100 - 4 = 4 + 3W - 4
96 = 3W
Divide both sided by 3
[tex]\frac{96}{3} = \frac{3W}{3}[/tex]
32 = W
W = 32
Recall that L = 4 + 2W
Substitute 32 for W
L = 4 + 2(32)
L = 4 + 64
L = 68
Hence the length and width of the field are 68ft anf 32ft respectively
