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A wire that is 0.20 meters long is moved perpendicularly through a magnetic field of strength 0.45 newtons/amperes meter at a speed of 10.0
meters/second. What is the emf produced?
OA.
10.65 volts
OB.
9.35 volts
C.
0.90 volts
OD
4.4 volts

Respuesta :

Answer:

Given:

length of the wire = 0.20 meters

magnetic field strength = 0.45 newtons/amperes meter

speed = 10.0 meters per second

emf = B * l * v 

B = flux density ; l = length of the wire ; v = velocity of the conductor

emf = 0.45 newtons / ampere meter * 0.20 meters * 10.0 meters/seconds

emf = 0.90 volts

The emf produced is 0.90 volts.

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

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