In a recent poll, 30 percent of adults said they wanted to "cut down or be free of gluten," according to The NDP Group, the market-research company that conducted the poll. A researcher wonders if a smaller proportion of students at her university would respond in the same fashion. Suppose the researcher conducts a survey of a random sample of 25 students at her university and five of them say they want to at least reduce gluten. A statistician carries out a significance test of the null hypothesis that the proportion wanting to reduce gluten at the university is the same as for all adults versus the alternative hypothesis that a smaller proportion p of students would say they want to reduce or be free of gluten. What is the value of the standardized test statistic for this significance test? A) – 0.100 B) – 1.250 C) 0.200 D) – 1.091

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Answer:

The value of the standardized test statistic for this significance test is -1.25.

Step-by-step explanation:

We are given that in a recent poll, 30 percent of adults said they wanted to "cut down or be free of gluten".

The researcher conducts a survey of a random sample of 25 students at her university and five of them say they want to at least reduce gluten.

Let p = population proportion of students wanting to reduce gluten at the university.

So, Null Hypothesis, [tex]H_0[/tex] : p = 30%      {means that the proportion wanting to reduce gluten at the university is the same as for all adults}

Alternate Hypothesis, [tex]H_A[/tex] : p < 30%     {means that a smaller proportion of students would say they want to reduce or be free of gluten}

The test statistics that would be used here One-sample z test for proportions;

                           T.S. =  [tex]\frac{\hat p-p}{\sqrt\frac{\hat p(1-\hat p)}{n} {} }[/tex]  ~ N(0,1)

where, [tex]\hat p[/tex] = sample proportion of students who would say they want to reduce or be free of gluten = [tex]\frac{5}{25}[/tex] = 0.20

            n = sample of students taken = 25

So, the test statistics  =  [tex]\frac{0.20-0.30}{\sqrt\frac{0.20(1-0.20)}{25} {} }[/tex]

                                     =  -1.25

The value of standardized z test statistic is -1.25.

Using the z-distribution, it is found that the value of the standardized test statistic for this significance test is:

D) –1.091

At the null hypothesis, we test if the proportion is of 0.3, that is:

[tex]H_0: p = 0.3[/tex]

At the alternative hypothesis, we test if the proportion is of less than 0.3, that is:

[tex]H_1: p < 0.3[/tex]

The test statistic is given by:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

In which:

  • [tex]\overline{p}[/tex] is the sample proportion.
  • p is the proportion tested at the null hypothesis.
  • n is the sample size.

For this problem, the parameters are:

[tex]p = 0.3, n = 25, \overline{p} = \frac{5}{25} = 0.2[/tex]

Hence, the value of the test statistic is:

[tex]z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]

[tex]z = \frac{0.2 - 0.3}{\sqrt{\frac{0.3(0.7)}{25}}}[/tex]

[tex]z = -1.091[/tex]

A similar problem is given at https://brainly.com/question/24166849