Respuesta :
Answer:
The current is [tex]I = 1 A[/tex]
The direction is anti-clockwise
Explanation:
The diagram for this question is shown on the first uploaded image
From the question we are told that
the length of the conducting rod is [tex]L = 25 \ cm = \frac{25}{100} = 2.5 \ m[/tex]
The resistance is [tex]R = 8 \Omega[/tex]
The magnetic field is [tex]B = 0.40\ T[/tex]
The speed of the rod is [tex]v = 6.0 m/s[/tex]
The emf induced is
[tex]\epsilon = BLv[/tex]
substituting values we have
[tex]\epsilon = 0.40 * 2.5 * 8[/tex]
[tex]\epsilon = 8V[/tex]
From ohm law the induced current would be
[tex]I = \frac{\epsilon}{R }[/tex]
substituting values we have
[tex]I = \frac{8}{8 }[/tex]
[tex]I = 1 A[/tex]
The direction anticlockwise this because according to lenze law the current due to change in magnetic field will act in the opposite direction of the force causing the magnetic field to change

The magnitude of the current will be:
"1 A (Anticlock wise direction)".
Direction and Magnitude
According to the question,
Conducting rod's length, L = 25 cm or,
= 2.5 m
Resistance, R = 8 Ω
Magnetic field, B = 0.40 T
Rod's speed, v = 6.0 m/s
We know the emf induced:
→ [tex]\epsilon[/tex] = BLv
By substituting the values,
= 0.40 × 2.5 × 8
= 8 V
By using Ohm's law,
→ I = [tex]\frac{\epsilon}{R}[/tex]
= [tex]\frac{8}{8}[/tex]
= 1 A (Anticlock wise)
Thus the approach above is appropriate.
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