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In the following reaction 6.13 g of water is actually produced, but the theoretical yield of water is 8.17 g. What is the percent yield of this reaction? *

85.0%
72.0%
75.0%
67.0%

In the following reaction 613 g of water is actually produced but the theoretical yield of water is 817 g What is the percent yield of this reaction 850 720 750 class=

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Eduard22sly

Answer:

75.0%

Explanation:

Data obtained from the question. This includes the following:

Actual yield = 6.13g

Theoretical yield = 8.17g

Percentage yield =...?

The percentage yield can be obtain by using the following formula:

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 6.13/8.17 x 100

Percentage yield = 75.0%

Therefore, the percentage yield of water from the reaction above is 75.0%

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