Respuesta :

Answer:

  factor out (1/2)e^(2x)

Step-by-step explanation:

Clearly, you factor out (1/2)e^(2x).

  [tex]\dfrac{e^{2x}(2x+5)}{2}-\dfrac{e^{2x}}{2}+C=\dfrac{e^{2x}}{2}\cdot((2x+5)-1)+C\\\\=\boxed{\dfrac{1}{2}e^{2x}(2x+4)+C}[/tex]