Respuesta :

Answer: 16.1

Step-by-step explanation:

x^2 = 8^2 + (28/2)^2

x^2=64 + 196

x^2= 260

Take the square root of 260 and get 16.1!

The value of x is x=16.1

Chord

The perpendicular from the center of a circle bisects the chord

Radius

A line from the center of the circle to the circumference of the circle is the radius of the circle

Lets connect the center of the circle to the other end of the chord that is at the circumference of circle

The diagram attached below

The line OA from the center bisects the chord

AB= half of 28 = 14

the triangle AOB forms a right angle triangle

apply Pythagorean theorem to find out the value of x

[tex]x^2=8^2+14^2\\x^2= 64+196\\x^2=260\\\sqrt{x^2}=\sqrt{260} \\ x=16.1[/tex]

The value of x is 16.1

Learn more information about 'perpendicular line ' here

brainly.com/question/4234327

Ver imagen lisboa