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Hydrogen sulfide and concentrated sulfuric acid react to form water and sulfur dioxide as shown in the following reaction:
H2S (g) + 3H2SO4 (I) = 4H2O (I) + 4SO2 (g)
If a sample of .500 moles of hydrogen sulfide was reacted with excess concentrated sulfuric acid, How many moles of sulfur dioxide would be produced?

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Answer:

2 moles of SO₂

Explanation:

Equation of reaction

H₂S + 3H₂SO₄ → 4H₂O + 4SO₂

From the equation of reaction above,

1 mole of H₂S will produce 4 moles of SO₂

1 mole of H₂S = 4 moles of SO₂

0.5moles of H₂S = zmoles of SO₂

z = (0.5*4) / 1

z = 2 moles of SO₂

0.5 moles of H₂S will produce 2 moles of SO₂

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