Respuesta :
0 = x + 2 + x^2
x^2 + x + 2 = 0
a = 1, b = 1, c = 2
discriminant = b^2 - 4ac = 1^2 - (4 x 1 x 2) = 1 - 8 = -7
x^2 + x + 2 = 0
a = 1, b = 1, c = 2
discriminant = b^2 - 4ac = 1^2 - (4 x 1 x 2) = 1 - 8 = -7
Answer:
value of the discriminant for the quadratic equation is, -7
Step-by-step explanation:
A quadratic equation is in the form of : [tex]ax^2+bx+c = 0[/tex] ...[1]
then the discriminant(D) is given by:
[tex]D = b^2-4ac[/tex]
Given the quadratic equation:
[tex]0 = x+2+x^2[/tex]
We can write this as:
[tex]x^2+x+2 = 0[/tex]
On comparing with [1] we have;
a = 1, b =1 and c = 2
then;
[tex]D = 1^2-4(1)(2) = 1-8 = -7[/tex]
Therefore, the value of the discriminant for the quadratic equation is, -7