Respuesta :
Given a standardized test with a mean score of 78 and a standard deviation of 5.9, a student who scored in the 60th percentile could have a score of:
a. 84
b. 72
c. 79
d. 76
the answer is c
Answer:
The score of Mr.Myles is between 56 and 88.
Step-by-step explanation:
Given : When Mrs. Myles gave a test, the scores were normally distributed with a mean of 72 and a standard deviation of 8.
To find : The class interval at 95% of her students scored between which two scores?
Solution :
We have given,
Mean [tex]\mu=72[/tex]
Standard deviation [tex]\sigma=8[/tex]
The class interval at 95% is given by
[tex]\mu-2\sigma\leq CI\leq \mu+2\sigma[/tex]
Substitute the values in the formula,
[tex]72-2(8)\leq CI\leq 72+2(8)[/tex]
[tex]72-16\leq CI\leq 72+16[/tex]
[tex]56\leq CI\leq 88[/tex]
Therefore, The score of Mr.Myles is between 56 and 88.
