Respuesta :
Using kinematics, the variables we know are:
Acceleration (due to gravity) = 9.81m/s^2 [down]
distance = 25m
Vi = 0m/s
Since we don't know time we can use the equation:
Vf^2 = Vi^2 + 2ad
Vf^2 = 0^2 + (2)(-9.81)(-25)
Vf^2 = 490.5m/s
Vf = 22m/s
Acceleration (due to gravity) = 9.81m/s^2 [down]
distance = 25m
Vi = 0m/s
Since we don't know time we can use the equation:
Vf^2 = Vi^2 + 2ad
Vf^2 = 0^2 + (2)(-9.81)(-25)
Vf^2 = 490.5m/s
Vf = 22m/s
we are given with an initial height of 25 meters in which the object is dropped freely from above. Hence teh kinematic equation that can be applied is 2ax = vf2 - v02 where a is the acceleration due to gravity and vo is equal to zero. Substiuting, vf is equal to C. 22 meters/ second