Respuesta :
pH + pOH = 14
11.8 + pOH = 14
pOH = 14 - 11.8
pOH = 2.2
[OH-] = 10 ^- pOH
[OH-] = 10 ^- 2.2
[OH-] = 6.33 x 10^-3 M
Answer B
hope this helps!
11.8 + pOH = 14
pOH = 14 - 11.8
pOH = 2.2
[OH-] = 10 ^- pOH
[OH-] = 10 ^- 2.2
[OH-] = 6.33 x 10^-3 M
Answer B
hope this helps!
We determine the concentration of OH- ions by calculating first the pOH first of the solution.
pH + pOH = 14
pOH = 14 - 11.8 = 2.2
pOH = -log (OH-) = 2.2
(OH-) = 6.33 x 10^-3 M
Therefore, the correct answer is option B.
pH + pOH = 14
pOH = 14 - 11.8 = 2.2
pOH = -log (OH-) = 2.2
(OH-) = 6.33 x 10^-3 M
Therefore, the correct answer is option B.