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meerkat18
A diploid cell in prophase I comes twice its number after it undergoes prophase II. In this case, when we represent the numbre of DNA content of the diploid cell as x, then the same cell after undergoing prophase II has a DNA count of 2x. That is for example, an initial count of 154 becomes 308 after prophase II.
gradman555p98x9p

The right answer is X/2

Prophase I and prophase II are stages of meiosis.

Meiosis consists in making two successive divisions starting from a single replication, if in the first stage of meiosis we have an X content, it will be divided in two to be distributed in the two daughter cells (during the anaphase I ). Each daughter cell will have X / 2 DNA content.

So the daughter cell will end up with X / 2 DNA content when it starts the second division (prophase II).

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