lawandap15
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how do you simpify the rational expression and State any excluded values.x^2-x-6/x+2


 A. x - 3, where x does not equal -2
 B. x -3, where x does not equal 3
 C. x - 2
 D., where x does not equal 2
1/x-2

Respuesta :

dalendrk
[tex]Domain:x\neq-2\\\\\dfrac{x^2-x-6}{x+2}=\dfrac{x^2+2x-3x-6}{x+2}=\dfrac{x(x+2)-3(x+2)}{x+2}\\\\=\dfrac{(x+2)(x-3)}{x+2}=x-3\\\\Answer:\boxed{A.\ x - 3,\ where\ x\ does\ not\ equal\ -2}[/tex]

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