Respuesta :
Answer:
Time taken by the car = 6 seconds.
Explanation:
Given:
Case 1:
Initial velocity of the car, [tex]v_i[/tex] = 0
Final velocity of the car, [tex]v_f[/tex] = 30 m/s
Time taken by the car, [tex]t[/tex] = 12 sec
Case 2:
Initial velocity of the car, [tex]v_i_2[/tex] = 0
Final velocity of the car, [tex]v_f_2[/tex] = 15 m/s
Solution:
Lets find the acceleration in first case:
⇒ acceleration (a) = (final velocity - initial velocity) / time
⇒ [tex]a=\frac{v_f-v_i}{t}[/tex]
⇒ [tex]a=\frac{30-0}{12}[/tex]
⇒ [tex]a=\frac{30}{12}[/tex]
⇒ [tex]a=2.5\ ms^-^2[/tex]
Using this acceleration value we can find the time taken in case 2:
⇒ time taken (t2) = (final velocity - initial velocity) / acceleration
⇒ [tex]t_2=\frac{v_f-v_i}{a}[/tex]
⇒ [tex]t_2=\frac{15-0}{2.5}[/tex]
⇒ [tex]t_2=\frac{15}{2.5}[/tex]
⇒ [tex]t_2=6\ sec[/tex]
So time taken by the car to go from rest to 15 m/s is 6 seconds.
Answer:
Time taken by the car = 6 seconds.
Explanation:
Given:
Case 1:
Initial velocity of the car, = 0
Final velocity of the car, = 30 m/s
Time taken by the car, = 12 sec
Case 2:
Initial velocity of the car, = 0
Final velocity of the car, = 15 m/s
Solution:
Lets find the acceleration in first case:
⇒ acceleration (a) = (final velocity - initial velocity) / time
⇒ Using this acceleration value we can find the time taken in case 2
⇒ time taken (t2) = (final velocity - initial velocity) / acceleration
So time taken by the car to go from rest to 15 m/s is 6 seconds.
