Respuesta :
Answer:
The tension in the tow rope pulling the log is 784.61 N
Explanation:
Given:
v = speed = 13 m/s
Pf = final power when the log is pulled = 8.5x10⁴W
Pi = average power = 7.48x10⁴W
The force required to move a car is equal to:
[tex]F_{i} =\frac{P_{i} }{v} =\frac{7.48x10^{4} }{13} =5753.85 N[/tex]
[tex]F_{f} =\frac{P_{f} }{v} =\frac{8.5x10^{4} }{13} =6538.46 N[/tex]
T = Ff - Fi = 6538.46 - 5753.85 = 784.61 N
Answer: 784.6 N
Explanation:
Given
Power of the motor, P1 = 7.48*10^4 W
Speed of the motor, v = 13 m/s
Power of the motor, P2 = 8.5*10^4 W
It is known that
Power = J/t, where
J = work, in joules
t = time, in seconds. Also,
Work = F * d, where
F = force
d = distance, thus on substituting, we have,
Power = Fd/t
Also, we know that
Velocity = d/t, where
d = distance,
t = time, thus, we could say that
Power = Force * Velocity
P = FV
To find the tension in the log, we use
F = P/V, where
P = P2 - P1
P = 8.5*10^4 - 7.48*10^4
P = 1.02*10^4 = 10200W
Force, F = 10200 / 13
F = 784.6 N
