Answer:
2653 turns
Explanation:
We are given that
Diameter,d=2 cm
Length of magnet,l=8 cm=[tex]8\times 10^{-2} m[/tex]
1m=100 cm
Magnetic field,B=0.1 T
Current,I=2.4 A
We are given that
Magnetic field of solenoid and magnetic are same and size of both solenoid and magnetic are also same.
Length of solenoid=[tex]8\times 10^{-2} m[/tex]
Magnetic field of solenoid
[tex]B=\frac{\mu_0NI}{l}[/tex]
Using the formula
[tex]0.1=\frac{4\pi\times 10^{-7}\times 2.4\times N}{8\times 10^{-2}}[/tex]
Where [tex]\mu_0=4\pi\times 10^{-7}[/tex]
[tex]N=\frac{0.1\times 8\times 10^{-2}}{4\pi\times 10^{-7}\times 2.4}=2653 turns[/tex]
