Answer:
The tangential speed of the ball is 11.213 m/s
Explanation:
The radius is equal:
[tex]r=2.3*sin70=2.161m[/tex] (ball rotates in a circle)
If the system is in equilibrium, the tension is:
[tex]Tcos70=mg\\Tsin70=\frac{mv^{2} }{r}[/tex]
Replacing:
[tex]\frac{mg}{cos70} sin70=\frac{mv^{2} }{r} \\Clearing-v:\\v=\sqrt{rgtan70}[/tex]
Replacing:
[tex]v=\sqrt{2.161x^{2}*9.8*tan70 } =11.213m/s[/tex]
