Answer:
[tex]\mu_p=3.2\\\\\sigma_p=0.2[/tex]
Step-by-step explanation:
-The number of males in the company is:
[tex]Males, n=\%\ Males\times Total\\\\=0.4\times 200\\\\=80[/tex]
#Given the proportion of males in the population is 40%(p=0.4) and the sample size, n=8
-The mean and standard deviation of a sample proportion is calculated as follows:
[tex]\mu=np\\\\=0.4\times 8\\\\\\\\=3.2\\\\\sigma_p=\sqrt{\frac{p(1-p)}{n}}\\\\\\=\sqrt{\frac{0.4(1-0.4)}{8}}\\\\\\\\=0.1732\approx0.2[/tex]
Hence, the mean of males is 3.2 and the standard deviation is 0.2
Answer:
mean: 3.2 standard deviation: 1.4
Step-by-step explanation:
its correct
