Answer:
2
Explanation:
m = Linear density = [tex]0.014\ kg/m[/tex]
T = Tension = [tex]323\ N[/tex]
f = Frequency = 20 Hz
l = Length of the wire = 7.6 m
The harmonic number is given by
[tex]n=f2l\sqrt{\dfrac{m}{T}}\\\Rightarrow n=20\times 2\times 7.6\times \sqrt{\dfrac{0.014}{323}}\\\Rightarrow n=2.00141126679\approx 2[/tex]
The lowest harmonic number n is 2