Respuesta :
Answer:
0.5433 is the probability that out of three executive job applicants, none lied on their application.
Step-by-step explanation:
We are given the following information:
We treat individuals lying on the resume as a success.
P(Individuals lie on resume) = 18.4% = 0.184
Then the number of job applicants follows a binomial distribution, where
[tex]P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}[/tex]
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 3
We have to evaluate:
P(None lied on resume)
[tex]P(x =0)\\\\= \binom{3}{0}(0.184)^0(1-0.184)^3\\\\= 0.5433[/tex]
0.5433 is the probability that out of three executive job applicants, none lied on their application.
