Answer:
a. Survey more students.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
The higher the confidene level, the higher the value of z is.
The margin of error is given by:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
The smaller the margin of error, the narrower the interval is.
What can they do to make a narrower interval?
As we saw from the equation above, the margin of error decreases as the sample size increases.
So the correct answer is:
a. Survey more students.
