Answer:
a) t₀ = 1.73205 s
b) 1.0 C
Step-by-step explanation:
(A)
The time dilation (t) observed by an observer at rest relative to the time (t₀) measured by observer in motion is;
[tex]t = \frac{t_0}{\sqrt{1 - \frac{V^2}{C^2}}}[/tex]
[tex]t_0 = t \sqrt{1 - \frac{V^2}{C^2}}[/tex] time measured by captain
⇒ [tex]t_0 = 2.0 \sqrt{1 - \frac{0.5^2C^2}{C^2}}[/tex] V = 0.5 c
⇒ t₀ = 1.73205 s
(B)
Speed of the light never exceeds by its real value. The speed of the light in any frame of reference is constant.
∵ It will be "1.0C" or just "C"