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The angle of inclination from the base of skyscraper A to the top of skyscraper B is approximately 12.8° If skyscraper B is 1479 feet tall how far apart are the two
skyscrapers? Assume the bases of the two buildings are at the same elevation.
feet.
The distance from skyscraper A to skyscraper B is
(Round to two decimal places as needed.)

Respuesta :

Answer:

6509.84 ft to the nearest hundredth.

Step-by-step explanation:

We have a right triangle in which the opposite side is 1479 ft and we need to find the adjacent side:

Tan 12.8 = opposite / adjacent side

tan 12.8 = 1479/ x

x = 1479/tan 12.8

= 6509.84 ft.

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