Answer:
6.598
Step-by-step explanation:
- A random sample of n = 1,045 young adults found that 60 % do not have a landline telephone number.
- We have to test the hypothesis that whether the data provide statistical evidence that more than 50 percent of all young adults do not have a landline telephone number.
- Let Null Hypothesis, H_o: p 0.50
- Alternate Hypothesis, H_1 : p > 0.50
- The test statistics that will be used here is One-sample proportion test;
Test = [tex]\frac{p' - p}{\sqrt{\frac{p'*(1 - p')}{n} } }[/tex] ~ N(0,1)
- Where, p' = % of young adults who do not have a landline telephone number in a sample of n is = 60%
- Where, n = sample of young adults = 1,045
- So, test statistics = [tex]\frac{0.6 - 0.5}{\sqrt{\frac{0.6*(1 - 0.6)}{1045} } }[/tex] = 6.598
- Hence, the test statistic for the test is 6.598.
Answer:
The test statistic value = 6.49
Step-by-step explanation:
Given Data;
n = 1045
P = 0.6
the null and alternative hypotheses can be defined as:
H0 : P = 0.50
H1 : p greater than 0.50
The test statistic value is calculated using the formula;
Substituting, we have
z = (0.60 - 0.50)/(√0.50(1-0.50)/1045)
z = 0.1/(√0.5*0.5)/1045)
= 0.1/√0.000239
= 0.1/0.0154
= 6.49
Note: The test statistic will be used to make decision about the hypothesis test.
