Respuesta :
Answer: The mass of [tex]CaCO_3[/tex] dissolve can be, 7.25 grams.
Explanation : Given,
Mass of [tex]HCl[/tex] = 5.30 g
Molar mass of [tex]HCl[/tex] = 36.5 g/mol
Molar mass of [tex]CaCO_3[/tex] = 100 g/mol
First we have to calculate the moles of [tex]HCl[/tex].
[tex]\text{Moles of }HCl=\frac{\text{Given mass }HCl}{\text{Molar mass }HCl}[/tex]
[tex]\text{Moles of }HCl=\frac{5.30g}{36.5g/mol}=0.145mol[/tex]
Now we have to calculate the moles of [tex]CaCO_3[/tex]
The balanced chemical equation is:
[tex]CaCO_3(s)+2HCl(aq)\rightarrow CaCl_2(aq)+H_2O(l)+CO_2(g)[/tex]
From the reaction, we conclude that
As, 2 mole of [tex]HCl[/tex] react with 1 mole of [tex]CaCO_3[/tex]
So, 0.145 mole of [tex]HCl[/tex] react with [tex]\frac{0.145}{2}=0.0725[/tex] mole of [tex]CaCO_3[/tex]
Now we have to calculate the mass of [tex]CaCO_3[/tex]
[tex]\text{ Mass of }CaCO_3=\text{ Moles of }CaCO_3\times \text{ Molar mass of }CaCO_3[/tex]
[tex]\text{ Mass of }CaCO_3=(0.0725moles)\times (100g/mole)=7.25g[/tex]
Therefore, the mass of [tex]CaCO_3[/tex] dissolve can be, 7.25 grams.
