Answer : The number of moles of oxygen in the reaction vessel is, 0.761 mole.
Explanation :
To calculate the number of moles of oxygen gas we are using ideal gas equation as follows:
[tex]PV=nRT[/tex]
where,
P = Pressure of [tex]O_2[/tex] gas = 84.8 atm
V = Volume of [tex]O_2[/tex] gas = 0.217 L
n = number of moles [tex]O_2[/tex] = ?
R = Gas constant = [tex]0.0821L.atm/mol.K[/tex]
T = Temperature of [tex]O_2[/tex] gas = [tex]21.6^oC=273+21.6=294.6K[/tex]
Now put all the given values in above equation, we get:
[tex]84.8atm\times 0.217L=n\times (0.0821L.atm/mol.K)\times 294.6K[/tex]
[tex]n=0.761mol[/tex]
Therefore, the number of moles of oxygen in the reaction vessel is, 0.761 mole.
