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In a region of space, a magnetic field points in the +x-direction (toward the right). Its magnitude varies with position according to the formula Bx=B0+bx, where B0 and b are positive constants, for x≥0. A flat coil of area A moves with uniform speed v from right to left with the plane of its area always perpendicular to this field. Part A What is the emf induced in this coil while it is to the right of the origin?

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lublana

Answer:

[tex]E=Abv[/tex]

Explanation:

We are given that

[tex]B_x=B_0+bx[/tex]

For [tex]x\geq 0[/tex]

Area of coil=A

Speed=v

We have to find the emf induced in the coil while it is to the right of the origin.

We know that induced emf

[tex]E=-\frac{d\phi}{dt}[/tex]

[tex]\phi=BA[/tex]

[tex]E=-\frac{d(A(B_0+bx)}{dt}[/tex]

[tex]E=-A(b)\frac{dx}{dt}[/tex]

We know that

[tex]v=-\frac{dx}{dt}[/tex]

Substitute the value

[tex]E=Abv[/tex]

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