Answer:
Cost of each IBM computer is $787.5
Step-by-step explanation:
Given
Ratio of the number of HP computers to IBM to Dell is 2:3:6.
Cost of HP computer = $750.
Cost of Dell computer costs 90% of the price of an HP computer.
Total Amount Spent = $1,650,000.
First, we need to calculate the cost of Dell computers
Cost of Dell Computers = 90% * Cost of HP computer
Cost of Dell Computers = 90% * $750
Cost of Dell Computers = $675
Then we calculate the number of each computer type;
For HP;
[tex]\frac{2}{2+3+6}[/tex] = [tex]\frac{2}{11}[/tex]
Number of HP = [tex]\frac{2}{11}[/tex] * 2200
Number of HP = 400
For Dell;
[tex]\frac{3}{2+3+6}[/tex] = [tex]\frac{3}{11}[/tex]
Number of Dell = [tex]\frac{3}{11}[/tex] * 2200
Number of Dell = 600
For IBM;
[tex]\frac{6}{2+3+6}[/tex] = [tex]\frac{6}{11}[/tex]
Number of Dell = [tex]\frac{6}{12}[/tex] * 2200
Number of Dell = 1200
So, the total amount spent on each type of computer is;
For HP = 400 * 750 = 300,000
For Dell = 600 * 675 = 405,000
Let x represent amount spent on each IBM computer
For IBM = 1200 * x = 1200x
Total = 300000 + 405000 + 1200x = $1,650,000.
$705,000 + 1200x = $1,650,000.
1200x = $1,650,000 - $705,000
1200x = $945,000
x = $945,000/1200
x = $787.5
Cost of each IBM computer is $787.5
