Answer:
[tex]P_{2} = 33.267\,psi[/tex]
Explanation:
Let assume that air in the tire behaves ideally. Afterwards, the following relation is used:
[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}[/tex]
The final pressure is:
[tex]P_{2} = \frac{T_{2}}{T_{1}}\cdot P_{1}[/tex]
[tex]P_{2} = \left(\frac{277.05\,K}{295.65\,K}\right)\cdot (35.5\,psi)[/tex]
[tex]P_{2} = 33.267\,psi[/tex]