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A packet switch has 5 users, each offering packets at a rate of 10 pps. The average length of the packets is 1024 bits. The packets switch needs to transmit this data over a 56-kbs WAN circuit. Given Queue depth = Utilization / (1-Utilization). Calculate the average number of packets in the queue (also called Queue depth).

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Chrisnando

Answer:

Average number of packets in queue(queue depth) = 10.63packets

Explanation:

We are given:

Number of users = 5

Rate= 10pps

Average packet length = 1024bits

To find the average number of packets (queue depth), we are given the formula:

[tex] Queue depth = \frac{Utilization}{1-Utilization}[/tex]

But we need to find utilization first, therefore

Utilization = load/ WAN

But load=5*10*1024bits =51200bps

Utilization = 51200/56000 = 0.914

Therefore,

[tex]Queue depth = \frac{0.914}{1-0.914}[/tex]

= 10.63 packets

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