Answer:
P(M | C) = 0.6.
P(C | M) = 0.2
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
So
P(M | C).
[tex]P(M|C) = \frac{P(M \cap C)}{P(C)} = \frac{0.12}{0.2} = 0.6[/tex]
(d) Find P(C | M).
[tex]P(C|M) = \frac{P(M \cap C)}{P(M)} = \frac{0.12}{0.6} = 0.2[/tex]