Let C be the event that a randomly chosen adult has some college education. Let M be the event that a randomly chosen adult is married. Given P(C) = .2, P(M) = .6 and P(C ∩ M) = .12, find each probability. (c) Find P(M | C). (Round your answer to 2 decimal places.) P(M | C) (d) Find P(C | M). (Round your answer to 2 decimal places.) P(C | M)

Respuesta :

Answer:

P(M | C) = 0.6.

P(C | M) = 0.2

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

So

P(M | C).

[tex]P(M|C) = \frac{P(M \cap C)}{P(C)} = \frac{0.12}{0.2} = 0.6[/tex]

(d) Find P(C | M).

[tex]P(C|M) = \frac{P(M \cap C)}{P(M)} = \frac{0.12}{0.6} = 0.2[/tex]