Respuesta :
Answer:
The solution of equation [tex]x^2+7x-4=0[/tex] is 0.53,-7.53.
Step-by-step explanation:
Given : Quadratic equation [tex]x^2+7x-4=0[/tex]
To find : The solution of equation ?
Solution :
The solution of the quadratic equation [tex]ax^2+bx+c=0[/tex] is [tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
Here, a=1, b=7 and c=-4.
Substitute the values,
[tex]x=\frac{-7\pm\sqrt{7^2-4(1)(-4)}}{2(1)}[/tex]
[tex]x=\frac{-7\pm\sqrt{65}}{2}[/tex]
[tex]x=\frac{-7+\sqrt{65}}{2},\frac{-7-\sqrt{65}}{2}[/tex]
[tex]x=0.53,-7.53[/tex]
Therefore, the solution of equation [tex]x^2+7x-4=0[/tex] is 0.53,-7.53.
