Answer:
- The solution would be unsaturated.
Explanation:
The data are garbled and difficult to decipher so i have to work with other data.
I will use the graph attached.
There, I have drawn two red lines that intersect at T = 60ºC and Solubility close the the middle point between 80 and 90 g/100g of H₂O, but a little bit above (closer to 90 than to 80 g/100g of H₂O).
That means that the solubility at 60ºC is close to 85g/100g of H₂O but a little bit above.
Then, if 85 g of KBr were dissolved in 100g of water at 60°C, the solution would be unsaturated: it can dissolve a little bit more of solute.
To understand how you use the solubility curve graphs:
For a given temperature:
- move vertically upward from the mark of the temperature, i.e. 60ºC, in this case.
- Intersect the curve that corresponds to your solute, i.e. KBr in this case
- Points on the line mean the solution is saturated.
- Points below the line correspond to unsaturated solutions
- Points above the line correspond to supersaturated solutions.
